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3900690753433 is a prime number
BaseRepresentation
bin111000110000110011010…
…010010110011110011001
3111210220100211211021020221
4320300303102112132121
51002402103313102213
612143541432120041
7551546516225035
oct70606322263631
914726324737227
103900690753433
11127430126a881
1252bb91536021
13223aab43b746
14d6b19d2b1c5
156b6ec71838d
hex38c33496799

3900690753433 has 2 divisors, whose sum is σ = 3900690753434. Its totient is φ = 3900690753432.

The previous prime is 3900690753431. The next prime is 3900690753439. The reversal of 3900690753433 is 3343570960093.

3900690753433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3747275180944 + 153415572489 = 1935788^2 + 391683^2 .

It is a cyclic number.

It is not a de Polignac number, because 3900690753433 - 21 = 3900690753431 is a prime.

Together with 3900690753431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (3900690753431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1950345376716 + 1950345376717.

It is an arithmetic number, because the mean of its divisors is an integer number (1950345376717).

Almost surely, 23900690753433 is an apocalyptic number.

It is an amenable number.

3900690753433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3900690753433 is an equidigital number, since it uses as much as digits as its factorization.

3900690753433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5511240, while the sum is 52.

The spelling of 3900690753433 in words is "three trillion, nine hundred billion, six hundred ninety million, seven hundred fifty-three thousand, four hundred thirty-three".