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39065552681 is a prime number
BaseRepresentation
bin100100011000011111…
…010000011100101001
310201211112201200202112
4210120133100130221
51120001240141211
625540234212105
72552036501411
oct443037203451
9121745650675
1039065552681
1115627538a31
1276a2b84035
1338b75b785c
141c68445641
15103995388b
hex9187d0729

39065552681 has 2 divisors, whose sum is σ = 39065552682. Its totient is φ = 39065552680.

The previous prime is 39065552677. The next prime is 39065552683. The reversal of 39065552681 is 18625556093.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35826918400 + 3238634281 = 189280^2 + 56909^2 .

It is an emirp because it is prime and its reverse (18625556093) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 39065552681 - 22 = 39065552677 is a prime.

It is a super-2 number, since 2×390655526812 (a number of 22 digits) contains 22 as substring.

Together with 39065552683, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (39065552683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19532776340 + 19532776341.

It is an arithmetic number, because the mean of its divisors is an integer number (19532776341).

Almost surely, 239065552681 is an apocalyptic number.

It is an amenable number.

39065552681 is a deficient number, since it is larger than the sum of its proper divisors (1).

39065552681 is an equidigital number, since it uses as much as digits as its factorization.

39065552681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 50.

The spelling of 39065552681 in words is "thirty-nine billion, sixty-five million, five hundred fifty-two thousand, six hundred eighty-one".