3913124497 has 2 divisors, whose sum is σ = 3913124498. Its totient is φ = 3913124496.

The previous prime is 3913124491. The next prime is 3913124503. The reversal of 3913124497 is 7944213193.

3913124497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (3913124491) and next prime (3913124503).

It can be written as a sum of positive squares in only one way, i.e., 3868715601 + 44408896 = 62199^2 + 6664^2 .

It is a cyclic number.

It is not a de Polignac number, because 3913124497 - 2³ = 3913124489 is a prime.

It is not a weakly prime, because it can be changed into another prime (3913124491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1956562248 + 1956562249.

It is an arithmetic number, because the mean of its divisors is an integer number (1956562249).

Almost surely, 2^3913124497 is an apocalyptic number.

It is an amenable number.

3913124497 is a deficient number, since it is larger than the sum of its proper divisors (1).

3913124497 is an equidigital number, since it uses as much as digits as its factorization.

3913124497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 163296, while the sum is 43.

The square root of 3913124497 is about 62554.9718008089. The cubic root of 3913124497 is about 1575.8246454354.

The spelling of 3913124497 in words is "three billion, nine hundred thirteen million, one hundred twenty-four thousand, four hundred ninety-seven".