Base | Representation |
---|---|
bin | 100100011100101100… |
… | …001001101101000001 |
3 | 10202000110100220122101 |
4 | 210130230021231001 |
5 | 1120122311314133 |
6 | 25551233110401 |
7 | 2553553603132 |
oct | 443454115501 |
9 | 122013326571 |
10 | 39136041793 |
11 | 156633034a2 |
12 | 77026b8401 |
13 | 38c9097ba4 |
14 | 1c73953c89 |
15 | 1040c2937d |
hex | 91cb09b41 |
39136041793 has 2 divisors, whose sum is σ = 39136041794. Its totient is φ = 39136041792.
The previous prime is 39136041773. The next prime is 39136041839. The reversal of 39136041793 is 39714063193.
It is an a-pointer prime, because the next prime (39136041839) can be obtained adding 39136041793 to its sum of digits (46).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22521605184 + 16614436609 = 150072^2 + 128897^2 .
It is a cyclic number.
It is not a de Polignac number, because 39136041793 - 25 = 39136041761 is a prime.
It is not a weakly prime, because it can be changed into another prime (39136041773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19568020896 + 19568020897.
It is an arithmetic number, because the mean of its divisors is an integer number (19568020897).
Almost surely, 239136041793 is an apocalyptic number.
It is an amenable number.
39136041793 is a deficient number, since it is larger than the sum of its proper divisors (1).
39136041793 is an equidigital number, since it uses as much as digits as its factorization.
39136041793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 367416, while the sum is 46.
The spelling of 39136041793 in words is "thirty-nine billion, one hundred thirty-six million, forty-one thousand, seven hundred ninety-three".
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