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39138271349869 is a prime number
BaseRepresentation
bin10001110011000100101101…
…10000101100110001101101
312010120120201102102221101201
420321202112300230301231
520112220134431143434
6215123512412405501
711146434564264466
oct1071422660546155
9163516642387351
1039138271349869
111151a4a193194a
124481313a76891
1318ab9529c2c13
14994433c7bd6d
1547d122564614
hex239896c2cc6d

39138271349869 has 2 divisors, whose sum is σ = 39138271349870. Its totient is φ = 39138271349868.

The previous prime is 39138271349741. The next prime is 39138271349887. The reversal of 39138271349869 is 96894317283193.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32999992571844 + 6138278778025 = 5744562^2 + 2477555^2 .

It is a cyclic number.

It is not a de Polignac number, because 39138271349869 - 27 = 39138271349741 is a prime.

It is a super-2 number, since 2×391382713498692 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (39138271340869) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19569135674934 + 19569135674935.

It is an arithmetic number, because the mean of its divisors is an integer number (19569135674935).

Almost surely, 239138271349869 is an apocalyptic number.

It is an amenable number.

39138271349869 is a deficient number, since it is larger than the sum of its proper divisors (1).

39138271349869 is an equidigital number, since it uses as much as digits as its factorization.

39138271349869 is an evil number, because the sum of its binary digits is even.

The product of its digits is 423263232, while the sum is 73.

The spelling of 39138271349869 in words is "thirty-nine trillion, one hundred thirty-eight billion, two hundred seventy-one million, three hundred forty-nine thousand, eight hundred sixty-nine".