Base | Representation |
---|---|
bin | 111000111101111000100… |
… | …001101000110001111001 |
3 | 111212020121202212021111101 |
4 | 320331320201220301321 |
5 | 1003114340221242421 |
6 | 12154223330131401 |
7 | 552554560635532 |
oct | 70757041506171 |
9 | 14766552767441 |
10 | 3914737290361 |
11 | 127a25a163987 |
12 | 532851720b61 |
13 | 225209592661 |
14 | d768d679689 |
15 | 6bc70990191 |
hex | 38f78868c79 |
3914737290361 has 2 divisors, whose sum is σ = 3914737290362. Its totient is φ = 3914737290360.
The previous prime is 3914737290341. The next prime is 3914737290433. The reversal of 3914737290361 is 1630927374193.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3860364377961 + 54372912400 = 1964781^2 + 233180^2 .
It is a cyclic number.
It is not a de Polignac number, because 3914737290361 - 211 = 3914737288313 is a prime.
It is not a weakly prime, because it can be changed into another prime (3914737290311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1957368645180 + 1957368645181.
It is an arithmetic number, because the mean of its divisors is an integer number (1957368645181).
Almost surely, 23914737290361 is an apocalyptic number.
It is an amenable number.
3914737290361 is a deficient number, since it is larger than the sum of its proper divisors (1).
3914737290361 is an equidigital number, since it uses as much as digits as its factorization.
3914737290361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5143824, while the sum is 55.
The spelling of 3914737290361 in words is "three trillion, nine hundred fourteen billion, seven hundred thirty-seven million, two hundred ninety thousand, three hundred sixty-one".
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