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3914737290433 is a prime number
BaseRepresentation
bin111000111101111000100…
…001101000110011000001
3111212020121202212021121001
4320331320201220303001
51003114340221243213
612154223330132001
7552554560635664
oct70757041506301
914766552767531
103914737290433
11127a25a163a42
12532851721001
132252095926b8
14d768d6796db
156bc709901dd
hex38f78868cc1

3914737290433 has 2 divisors, whose sum is σ = 3914737290434. Its totient is φ = 3914737290432.

The previous prime is 3914737290361. The next prime is 3914737290437. The reversal of 3914737290433 is 3340927374193.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3200495954049 + 714241336384 = 1788993^2 + 845128^2 .

It is a cyclic number.

It is not a de Polignac number, because 3914737290433 - 213 = 3914737282241 is a prime.

It is not a weakly prime, because it can be changed into another prime (3914737290437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1957368645216 + 1957368645217.

It is an arithmetic number, because the mean of its divisors is an integer number (1957368645217).

Almost surely, 23914737290433 is an apocalyptic number.

It is an amenable number.

3914737290433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3914737290433 is an equidigital number, since it uses as much as digits as its factorization.

3914737290433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10287648, while the sum is 55.

The spelling of 3914737290433 in words is "three trillion, nine hundred fourteen billion, seven hundred thirty-seven million, two hundred ninety thousand, four hundred thirty-three".