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39257000693 is a prime number
BaseRepresentation
bin100100100011111001…
…100100101011110101
310202022212222021001122
4210203321210223311
51120344243010233
630011233433325
72556553000031
oct444371445365
9122285867048
1039257000693
111571560a729
12773710b845
1339181693c1
141c85a3d1c1
15104b66dd98
hex923e64af5

39257000693 has 2 divisors, whose sum is σ = 39257000694. Its totient is φ = 39257000692.

The previous prime is 39257000663. The next prime is 39257000771. The reversal of 39257000693 is 39600075293.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37675586404 + 1581414289 = 194102^2 + 39767^2 .

It is an emirp because it is prime and its reverse (39600075293) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 39257000693 - 28 = 39257000437 is a prime.

It is a super-2 number, since 2×392570006932 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (39257000603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19628500346 + 19628500347.

It is an arithmetic number, because the mean of its divisors is an integer number (19628500347).

Almost surely, 239257000693 is an apocalyptic number.

It is an amenable number.

39257000693 is a deficient number, since it is larger than the sum of its proper divisors (1).

39257000693 is an equidigital number, since it uses as much as digits as its factorization.

39257000693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 306180, while the sum is 44.

The spelling of 39257000693 in words is "thirty-nine billion, two hundred fifty-seven million, six hundred ninety-three", and thus it is an aban number.