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3934742199503 = 13799328514071
BaseRepresentation
bin111001010000100000111…
…010010011110011001111
3111221011020221121221211012
4321100200322103303033
51003431323000341003
612211332352515435
7554163402600023
oct71204072236317
914834227557735
103934742199503
111287795436245
125366b524bb7b
13227076c988bb
14d862a47c383
156c541d7a8d8
hex39420e93ccf

3934742199503 has 4 divisors (see below), whose sum is σ = 3934770851568. Its totient is φ = 3934713547440.

The previous prime is 3934742199457. The next prime is 3934742199539. The reversal of 3934742199503 is 3059912474393.

3934742199503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3934742199503 - 210 = 3934742198479 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3934742199803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14119043 + ... + 14395028.

It is an arithmetic number, because the mean of its divisors is an integer number (983692712892).

Almost surely, 23934742199503 is an apocalyptic number.

3934742199503 is a deficient number, since it is larger than the sum of its proper divisors (28652065).

3934742199503 is a wasteful number, since it uses less digits than its factorization.

3934742199503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28652064.

The product of its (nonzero) digits is 22044960, while the sum is 59.

The spelling of 3934742199503 in words is "three trillion, nine hundred thirty-four billion, seven hundred forty-two million, one hundred ninety-nine thousand, five hundred three".

Divisors: 1 137993 28514071 3934742199503