Base | Representation |
---|---|
bin | 111001010110001010001… |
… | …011101000110001101111 |
3 | 111221201220100200121201202 |
4 | 321112022023220301233 |
5 | 1004031231122114342 |
6 | 12214214031400115 |
7 | 554466531335045 |
oct | 71261213506157 |
9 | 14851810617652 |
10 | 3940803316847 |
11 | 128a315810431 |
12 | 53790708303b |
13 | 227801913077 |
14 | d8a4343a395 |
15 | 6c799037332 |
hex | 3958a2e8c6f |
3940803316847 has 2 divisors, whose sum is σ = 3940803316848. Its totient is φ = 3940803316846.
The previous prime is 3940803316811. The next prime is 3940803316859. The reversal of 3940803316847 is 7486133080493.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3940803316847 - 28 = 3940803316591 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3940803316792 and 3940803316801.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3940803316867) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1970401658423 + 1970401658424.
It is an arithmetic number, because the mean of its divisors is an integer number (1970401658424).
Almost surely, 23940803316847 is an apocalyptic number.
3940803316847 is a deficient number, since it is larger than the sum of its proper divisors (1).
3940803316847 is an equidigital number, since it uses as much as digits as its factorization.
3940803316847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10450944, while the sum is 56.
The spelling of 3940803316847 in words is "three trillion, nine hundred forty billion, eight hundred three million, three hundred sixteen thousand, eight hundred forty-seven".
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