Base | Representation |
---|---|
bin | 111001011000100101001… |
… | …100100111110011100101 |
3 | 111221222121121102012222212 |
4 | 321120211030213303211 |
5 | 1004102042413342433 |
6 | 12215324054133205 |
7 | 554621141213345 |
oct | 71304514476345 |
9 | 14858547365885 |
10 | 3943404043493 |
11 | 129042a8618a2 |
12 | 538312051205 |
13 | 227b2767b985 |
14 | d8c0c9cad25 |
15 | 6c89c50cd48 |
hex | 39625327ce5 |
3943404043493 has 2 divisors, whose sum is σ = 3943404043494. Its totient is φ = 3943404043492.
The previous prime is 3943404043429. The next prime is 3943404043511.
3943404043493 is nontrivially palindromic in base 10.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3615101400964 + 328302642529 = 1901342^2 + 572977^2 .
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 3943404043493 - 26 = 3943404043429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3943404040493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1971702021746 + 1971702021747.
It is an arithmetic number, because the mean of its divisors is an integer number (1971702021747).
Almost surely, 23943404043493 is an apocalyptic number.
It is an amenable number.
3943404043493 is a deficient number, since it is larger than the sum of its proper divisors (1).
3943404043493 is an equidigital number, since it uses as much as digits as its factorization.
3943404043493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6718464, while the sum is 50.
The spelling of 3943404043493 in words is "three trillion, nine hundred forty-three billion, four hundred four million, forty-three thousand, four hundred ninety-three".
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