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394361163793 is a prime number
BaseRepresentation
bin1011011110100011100…
…00011101000000010001
31101200220201002210220101
411233101300131000101
522430122424220133
6501100024212401
740330431404212
oct5572160350021
91350821083811
10394361163793
1114227a661293
126451a90a101
132b25a336c7c
1415131329409
15a3d185237d
hex5bd1c1d011

394361163793 has 2 divisors, whose sum is σ = 394361163794. Its totient is φ = 394361163792.

The previous prime is 394361163787. The next prime is 394361163797. The reversal of 394361163793 is 397361163493.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 393621976449 + 739187344 = 627393^2 + 27188^2 .

It is a cyclic number.

It is not a de Polignac number, because 394361163793 - 229 = 393824292881 is a prime.

It is not a weakly prime, because it can be changed into another prime (394361163797) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 197180581896 + 197180581897.

It is an arithmetic number, because the mean of its divisors is an integer number (197180581897).

Almost surely, 2394361163793 is an apocalyptic number.

It is an amenable number.

394361163793 is a deficient number, since it is larger than the sum of its proper divisors (1).

394361163793 is an equidigital number, since it uses as much as digits as its factorization.

394361163793 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6613488, while the sum is 55.

The spelling of 394361163793 in words is "three hundred ninety-four billion, three hundred sixty-one million, one hundred sixty-three thousand, seven hundred ninety-three".