Base | Representation |
---|---|
bin | 111001011010110000111… |
… | …001111110100110010001 |
3 | 111222012122221220211200122 |
4 | 321122300321332212101 |
5 | 1004121342434410403 |
6 | 12220352424400025 |
7 | 555033212221604 |
oct | 71326071764621 |
9 | 14865587824618 |
10 | 3945747966353 |
11 | 1291422952826 |
12 | 538867016015 |
13 | 22810c16208b |
14 | d8d9201033b |
15 | 6c9881a8838 |
hex | 396b0e7e991 |
3945747966353 has 4 divisors (see below), whose sum is σ = 4073030158848. Its totient is φ = 3818465773860.
The previous prime is 3945747966337. The next prime is 3945747966397. The reversal of 3945747966353 is 3536697475493.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3945747966353 - 24 = 3945747966337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3945747966053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63641096201 + ... + 63641096262.
It is an arithmetic number, because the mean of its divisors is an integer number (1018257539712).
Almost surely, 23945747966353 is an apocalyptic number.
It is an amenable number.
3945747966353 is a deficient number, since it is larger than the sum of its proper divisors (127282192495).
3945747966353 is a wasteful number, since it uses less digits than its factorization.
3945747966353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127282192494.
The product of its digits is 1543147200, while the sum is 71.
The spelling of 3945747966353 in words is "three trillion, nine hundred forty-five billion, seven hundred forty-seven million, nine hundred sixty-six thousand, three hundred fifty-three".
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