Base | Representation |
---|---|
bin | 1011011111000000110… |
… | …01101100101110101101 |
3 | 1101201112211102022210201 |
4 | 11233200121230232231 |
5 | 22431123323412013 |
6 | 501140242233501 |
7 | 40336503641266 |
oct | 5574031545655 |
9 | 1351484368721 |
10 | 394606857133 |
11 | 142396313335 |
12 | 64589055891 |
13 | 2b2991cc348 |
14 | 15155c0396d |
15 | a3e81d53dd |
hex | 5be066cbad |
394606857133 has 2 divisors, whose sum is σ = 394606857134. Its totient is φ = 394606857132.
The previous prime is 394606857103. The next prime is 394606857191. The reversal of 394606857133 is 331758606493.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 239006587689 + 155600269444 = 488883^2 + 394462^2 .
It is a cyclic number.
It is not a de Polignac number, because 394606857133 - 25 = 394606857101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (394606857103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 197303428566 + 197303428567.
It is an arithmetic number, because the mean of its divisors is an integer number (197303428567).
Almost surely, 2394606857133 is an apocalyptic number.
It is an amenable number.
394606857133 is a deficient number, since it is larger than the sum of its proper divisors (1).
394606857133 is an equidigital number, since it uses as much as digits as its factorization.
394606857133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9797760, while the sum is 55.
The spelling of 394606857133 in words is "three hundred ninety-four billion, six hundred six million, eight hundred fifty-seven thousand, one hundred thirty-three".
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