Base | Representation |
---|---|
bin | 111001011101010010110… |
… | …110010010111100110011 |
3 | 111222110200022022212212222 |
4 | 321131102312102330303 |
5 | 1004142424004111011 |
6 | 12221522202111255 |
7 | 555160432654520 |
oct | 71352266227463 |
9 | 14873608285788 |
10 | 3948464910131 |
11 | 1292597561905 |
12 | 5392a4aab52b |
13 | 228452ccbb11 |
14 | d916cbb4147 |
15 | 6ca96988ddb |
hex | 39752d92f33 |
3948464910131 has 16 divisors (see below), whose sum is σ = 4797572281344. Its totient is φ = 3176170524384.
The previous prime is 3948464910067. The next prime is 3948464910199. The reversal of 3948464910131 is 1310194648493.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 3948464910131 - 26 = 3948464910067 is a prime.
It is a super-2 number, since 2×39484649101312 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (53).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3948464916131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 231355871 + ... + 231372936.
It is an arithmetic number, because the mean of its divisors is an integer number (299848267584).
Almost surely, 23948464910131 is an apocalyptic number.
3948464910131 is a deficient number, since it is larger than the sum of its proper divisors (849107371213).
3948464910131 is a wasteful number, since it uses less digits than its factorization.
3948464910131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 462728890.
The product of its (nonzero) digits is 2239488, while the sum is 53.
The spelling of 3948464910131 in words is "three trillion, nine hundred forty-eight billion, four hundred sixty-four million, nine hundred ten thousand, one hundred thirty-one".
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