Base | Representation |
---|---|
bin | 111001011110101100011… |
… | …000011110101011110001 |
3 | 111222121112222212011020021 |
4 | 321132230120132223301 |
5 | 1004204013030341223 |
6 | 12222331222043441 |
7 | 555242602615534 |
oct | 71365430365361 |
9 | 14877488764207 |
10 | 3949967043313 |
11 | 1293198469795 |
12 | 539643b79581 |
13 | 22863228a015 |
14 | d92724b0a1b |
15 | 6cb337a565d |
hex | 397ac61eaf1 |
3949967043313 has 4 divisors (see below), whose sum is σ = 4046307702948. Its totient is φ = 3853626383680.
The previous prime is 3949967043193. The next prime is 3949967043317. The reversal of 3949967043313 is 3133407699493.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 447484737249 + 3502482306064 = 668943^2 + 1871492^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3949967043313 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3949967043317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48170329756 + ... + 48170329837.
It is an arithmetic number, because the mean of its divisors is an integer number (1011576925737).
Almost surely, 23949967043313 is an apocalyptic number.
It is an amenable number.
3949967043313 is a deficient number, since it is larger than the sum of its proper divisors (96340659635).
3949967043313 is an equidigital number, since it uses as much as digits as its factorization.
3949967043313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96340659634.
The product of its (nonzero) digits is 39680928, while the sum is 61.
The spelling of 3949967043313 in words is "three trillion, nine hundred forty-nine billion, nine hundred sixty-seven million, forty-three thousand, three hundred thirteen".
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