Base | Representation |
---|---|
bin | 111001100010100100110… |
… | …101100011001011000101 |
3 | 112000000022111101022002020 |
4 | 321202210311203023011 |
5 | 1004241032131212240 |
6 | 12224301004433353 |
7 | 555451106312250 |
oct | 71424465431305 |
9 | 15000274338066 |
10 | 3954135413445 |
11 | 1294a373a1988 |
12 | 53a407b48859 |
13 | 228b47a3cc19 |
14 | d9549d32097 |
15 | 6ccc96d80d0 |
hex | 398a4d632c5 |
3954135413445 has 32 divisors (see below), whose sum is σ = 7231472670720. Its totient is φ = 1807341353280.
The previous prime is 3954135413443. The next prime is 3954135413453. The reversal of 3954135413445 is 5443145314593.
It is not a de Polignac number, because 3954135413445 - 21 = 3954135413443 is a prime.
It is a super-2 number, since 2×39541354134452 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3954135413441) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2018935 + ... + 3461844.
It is an arithmetic number, because the mean of its divisors is an integer number (225983520960).
Almost surely, 23954135413445 is an apocalyptic number.
3954135413445 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
3954135413445 is a deficient number, since it is larger than the sum of its proper divisors (3277337257275).
3954135413445 is a wasteful number, since it uses less digits than its factorization.
3954135413445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5487665.
The product of its digits is 7776000, while the sum is 51.
The spelling of 3954135413445 in words is "three trillion, nine hundred fifty-four billion, one hundred thirty-five million, four hundred thirteen thousand, four hundred forty-five".
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