3970012550269 has 2 divisors, whose sum is σ = 3970012550270. Its totient is φ = 3970012550268.

The previous prime is 3970012550237. The next prime is 3970012550279. The reversal of 3970012550269 is 9620552100793.

3970012550269 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3927380624644 + 42631925625 = 1981762^2 + 206475^2 .

It is an emirp because it is prime and its reverse (9620552100793) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3970012550269 - 2⁵ = 3970012550237 is a prime.

It is a super-3 number, since 3×3970012550269³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3970012550279) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1985006275134 + 1985006275135.

It is an arithmetic number, because the mean of its divisors is an integer number (1985006275135).

Almost surely, 2^{3970012550269} is an apocalyptic number.

It is an amenable number.

3970012550269 is a deficient number, since it is larger than the sum of its proper divisors (1).

3970012550269 is an equidigital number, since it uses as much as digits as its factorization.

3970012550269 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1020600, while the sum is 49.

The spelling of 3970012550269 in words is "three trillion, nine hundred seventy billion, twelve million, five hundred fifty thousand, two hundred sixty-nine".