Base | Representation |
---|---|
bin | 111001111010110011011… |
… | …001101101111011000011 |
3 | 112002111110110121212010101 |
4 | 321322303121231323003 |
5 | 1010202321243020314 |
6 | 12244242214343231 |
7 | 560361550134664 |
oct | 71726331557303 |
9 | 15074413555111 |
10 | 3980149579459 |
11 | 12a4a76747939 |
12 | 54346805ab17 |
13 | 22b432403471 |
14 | da8d6c7336b |
15 | 6d7ed439174 |
hex | 39eb366dec3 |
3980149579459 has 2 divisors, whose sum is σ = 3980149579460. Its totient is φ = 3980149579458.
The previous prime is 3980149579457. The next prime is 3980149579463. The reversal of 3980149579459 is 9549759410893.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3980149579459 - 21 = 3980149579457 is a prime.
It is a super-3 number, since 3×39801495794593 (a number of 39 digits) contains 333 as substring.
Together with 3980149579457, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 3980149579391 and 3980149579400.
It is not a weakly prime, because it can be changed into another prime (3980149579457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1990074789729 + 1990074789730.
It is an arithmetic number, because the mean of its divisors is an integer number (1990074789730).
Almost surely, 23980149579459 is an apocalyptic number.
3980149579459 is a deficient number, since it is larger than the sum of its proper divisors (1).
3980149579459 is an equidigital number, since it uses as much as digits as its factorization.
3980149579459 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 440899200, while the sum is 73.
The spelling of 3980149579459 in words is "three trillion, nine hundred eighty billion, one hundred forty-nine million, five hundred seventy-nine thousand, four hundred fifty-nine".
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