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3981679425313 is a prime number
BaseRepresentation
bin111001111100001110100…
…101100111011100100001
3112002122102002022002002221
4321330032211213130201
51010213434413102223
612245054104311041
7560444504456662
oct71741645473441
915078362262087
103981679425313
1112a5691262757
12543814472481
1322b6173454b5
14daa00105369
156d88c8cbb5d
hex39f0e967721

3981679425313 has 2 divisors, whose sum is σ = 3981679425314. Its totient is φ = 3981679425312.

The previous prime is 3981679425263. The next prime is 3981679425359. The reversal of 3981679425313 is 3135249761893.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3144688648929 + 836990776384 = 1773327^2 + 914872^2 .

It is an emirp because it is prime and its reverse (3135249761893) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3981679425313 is a prime.

It is not a weakly prime, because it can be changed into another prime (3981679422313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1990839712656 + 1990839712657.

It is an arithmetic number, because the mean of its divisors is an integer number (1990839712657).

Almost surely, 23981679425313 is an apocalyptic number.

It is an amenable number.

3981679425313 is a deficient number, since it is larger than the sum of its proper divisors (1).

3981679425313 is an equidigital number, since it uses as much as digits as its factorization.

3981679425313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 29393280, while the sum is 61.

The spelling of 3981679425313 in words is "three trillion, nine hundred eighty-one billion, six hundred seventy-nine million, four hundred twenty-five thousand, three hundred thirteen".