3983400041713 has 2 divisors, whose sum is σ = 3983400041714. Its totient is φ = 3983400041712.

The previous prime is 3983400041689. The next prime is 3983400041717. The reversal of 3983400041713 is 3171400043893.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3893766867169 + 89633174544 = 1973263^2 + 299388^2 .

It is a cyclic number.

It is not a de Polignac number, because 3983400041713 - 2²⁵ = 3983366487281 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3983400041713.

It is not a weakly prime, because it can be changed into another prime (3983400041717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1991700020856 + 1991700020857.

It is an arithmetic number, because the mean of its divisors is an integer number (1991700020857).

Almost surely, 2^{3983400041713} is an apocalyptic number.

It is an amenable number.

3983400041713 is a deficient number, since it is larger than the sum of its proper divisors (1).

3983400041713 is an equidigital number, since it uses as much as digits as its factorization.

3983400041713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 43.

The spelling of 3983400041713 in words is "three trillion, nine hundred eighty-three billion, four hundred million, forty-one thousand, seven hundred thirteen".