Base | Representation |
---|---|
bin | 111001111101110101001… |
… | …001001111110011110101 |
3 | 112002210211222221110002102 |
4 | 321331311021033303311 |
5 | 1010231000402313332 |
6 | 12245540531151445 |
7 | 560535236456225 |
oct | 71756511176365 |
9 | 15083758843072 |
10 | 3983400041717 |
11 | 12a6394527288 |
12 | 544014745585 |
13 | 22b82c95c905 |
14 | dab24836085 |
15 | 6d93d9a4062 |
hex | 39f7524fcf5 |
3983400041717 has 2 divisors, whose sum is σ = 3983400041718. Its totient is φ = 3983400041716.
The previous prime is 3983400041713. The next prime is 3983400041737. The reversal of 3983400041717 is 7171400043893.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3344944708561 + 638455333156 = 1828919^2 + 799034^2 .
It is a cyclic number.
It is not a de Polignac number, because 3983400041717 - 22 = 3983400041713 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3983400041713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1991700020858 + 1991700020859.
It is an arithmetic number, because the mean of its divisors is an integer number (1991700020859).
Almost surely, 23983400041717 is an apocalyptic number.
It is an amenable number.
3983400041717 is a deficient number, since it is larger than the sum of its proper divisors (1).
3983400041717 is an equidigital number, since it uses as much as digits as its factorization.
3983400041717 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 508032, while the sum is 47.
The spelling of 3983400041717 in words is "three trillion, nine hundred eighty-three billion, four hundred million, forty-one thousand, seven hundred seventeen".
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