Base | Representation |
---|---|
bin | 1110111000011100… |
… | …1110100011010001 |
3 | 101022102001112011212 |
4 | 3232013032203101 |
5 | 31140141401032 |
6 | 1500223545505 |
7 | 200665565123 |
oct | 35607164321 |
9 | 11272045155 |
10 | 3994872017 |
11 | 1770001524 |
12 | 935a5b295 |
13 | 4b88475c6 |
14 | 29c7bb213 |
15 | 185ab0bb2 |
hex | ee1ce8d1 |
3994872017 has 2 divisors, whose sum is σ = 3994872018. Its totient is φ = 3994872016.
The previous prime is 3994871977. The next prime is 3994872031. The reversal of 3994872017 is 7102784993.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2306976961 + 1687895056 = 48031^2 + 41084^2 .
It is an emirp because it is prime and its reverse (7102784993) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3994872017 - 214 = 3994855633 is a prime.
It is not a weakly prime, because it can be changed into another prime (3994872317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1997436008 + 1997436009.
It is an arithmetic number, because the mean of its divisors is an integer number (1997436009).
Almost surely, 23994872017 is an apocalyptic number.
It is an amenable number.
3994872017 is a deficient number, since it is larger than the sum of its proper divisors (1).
3994872017 is an equidigital number, since it uses as much as digits as its factorization.
3994872017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 762048, while the sum is 50.
The square root of 3994872017 is about 63204.9999367139. Note that the first 4 decimals coincide. The cubic root of 3994872017 is about 1586.7224147481.
The spelling of 3994872017 in words is "three billion, nine hundred ninety-four million, eight hundred seventy-two thousand, seventeen".
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