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4000000000011 = 31333333333337
BaseRepresentation
bin111010001101010010100…
…101000100000000001011
3112011101200212200200221120
4322031102211010000023
51011014000000000021
612301324042010323
7561663505003131
oct72152245040013
915141625620846
104000000000011
1113024327a1684
12547287aa69a3
13230276ac8742
14db85b33d751
156e0b0eaa2c6
hex3a35294400b

4000000000011 has 4 divisors (see below), whose sum is σ = 5333333333352. Its totient is φ = 2666666666672.

The previous prime is 3999999999967. The next prime is 4000000000039. The reversal of 4000000000011 is 1100000000004.

4000000000011 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4000000000011 - 223 = 3999991611403 is a prime.

4000000000011 is a modest number, since divided by 11 gives 4 as remainder.

It is not an unprimeable number, because it can be changed into a prime (4000000020011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 666666666666 + ... + 666666666671.

It is an arithmetic number, because the mean of its divisors is an integer number (1333333333338).

Almost surely, 24000000000011 is an apocalyptic number.

4000000000011 is a deficient number, since it is larger than the sum of its proper divisors (1333333333341).

4000000000011 is a wasteful number, since it uses less digits than its factorization.

4000000000011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1333333333340.

The product of its (nonzero) digits is 4, while the sum is 6.

Adding to 4000000000011 its reverse (1100000000004), we get a palindrome (5100000000015).

The spelling of 4000000000011 in words is "four trillion, eleven", and thus it is an aban number.

Divisors: 1 3 1333333333337 4000000000011