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4000130221341 = 31333376740447
BaseRepresentation
bin111010001101011010010…
…101110100010100011101
3112011102000221201122000210
4322031122111310110131
51011014231314040331
612301345013043033
7561666645605142
oct72153225642435
915142027648023
104000130221341
11130249a254911
12547303626479
13230297a90b97
14db87075a3c9
156e0bc62e446
hex3a35a57451d

4000130221341 has 4 divisors (see below), whose sum is σ = 5333506961792. Its totient is φ = 2666753480892.

The previous prime is 4000130221303. The next prime is 4000130221361. The reversal of 4000130221341 is 1431220310004.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4000130221341 - 218 = 4000129959197 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4000130221301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 666688370221 + ... + 666688370226.

It is an arithmetic number, because the mean of its divisors is an integer number (1333376740448).

Almost surely, 24000130221341 is an apocalyptic number.

It is an amenable number.

4000130221341 is a deficient number, since it is larger than the sum of its proper divisors (1333376740451).

4000130221341 is a wasteful number, since it uses less digits than its factorization.

4000130221341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1333376740450.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 4000130221341 its reverse (1431220310004), we get a palindrome (5431350531345).

The spelling of 4000130221341 in words is "four trillion, one hundred thirty million, two hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 3 1333376740447 4000130221341