Base | Representation |
---|---|
bin | 100101010000010001… |
… | …000111000001000101 |
3 | 10211020202122001020002 |
4 | 211100101013001011 |
5 | 1123410322240013 |
6 | 30213144051045 |
7 | 2614162006346 |
oct | 452021070105 |
9 | 124222561202 |
10 | 40001368133 |
11 | 15a67802a31 |
12 | 7904463a85 |
13 | 3a064411cc |
14 | 1d168460cd |
15 | 1091ba7358 |
hex | 950447045 |
40001368133 has 4 divisors (see below), whose sum is σ = 40852461120. Its totient is φ = 39150275148.
The previous prime is 40001368129. The next prime is 40001368139. The reversal of 40001368133 is 33186310004.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 40001368133 - 22 = 40001368129 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40001368096 and 40001368105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40001368139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425546423 + ... + 425546516.
It is an arithmetic number, because the mean of its divisors is an integer number (10213115280).
Almost surely, 240001368133 is an apocalyptic number.
It is an amenable number.
40001368133 is a deficient number, since it is larger than the sum of its proper divisors (851092987).
40001368133 is an equidigital number, since it uses as much as digits as its factorization.
40001368133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 851092986.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 40001368133 its reverse (33186310004), we get a palindrome (73187678137).
The spelling of 40001368133 in words is "forty billion, one million, three hundred sixty-eight thousand, one hundred thirty-three".
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