400024113 has 4 divisors (see below), whose sum is σ = 533365488. Its totient is φ = 266682740.

The previous prime is 400024111. The next prime is 400024123. The reversal of 400024113 is 311420004.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 400024113 - 2¹ = 400024111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 400024092 and 400024101.

It is not an unprimeable number, because it can be changed into a prime (400024111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66670683 + ... + 66670688.

It is an arithmetic number, because the mean of its divisors is an integer number (133341372).

Almost surely, 2^400024113 is an apocalyptic number.

It is an amenable number.

400024113 is a deficient number, since it is larger than the sum of its proper divisors (133341375).

400024113 is a wasteful number, since it uses less digits than its factorization.

400024113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 133341374.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 400024113 is about 20000.6028159153. The cubic root of 400024113 is about 736.8211049392.

Adding to 400024113 its reverse (311420004), we get a palindrome (711444117).

The spelling of 400024113 in words is "four hundred million, twenty-four thousand, one hundred thirteen".