Base | Representation |
---|---|
bin | 101101011110100110101111… |
… | …1000010001111001110001111 |
3 | 1221110101112210001212212111121 |
4 | 1122331031133002033032033 |
5 | 404413100033132414203 |
6 | 3534443255500301411 |
7 | 150155153013401653 |
oct | 13275153702171617 |
9 | 1843345701785447 |
10 | 400030553404303 |
11 | 10650a006692558 |
12 | 38a48726b41867 |
13 | 14229947475a03 |
14 | 70ad82138aa63 |
15 | 313aaa561e0bd |
hex | 16bd35f08f38f |
400030553404303 has 4 divisors (see below), whose sum is σ = 400124479342680. Its totient is φ = 399936627465928.
The previous prime is 400030553404259. The next prime is 400030553404331. The reversal of 400030553404303 is 303404355030004.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 400030553404303 - 221 = 400030551307151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (400030553404403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46962962800 + ... + 46962971317.
It is an arithmetic number, because the mean of its divisors is an integer number (100031119835670).
Almost surely, 2400030553404303 is an apocalyptic number.
400030553404303 is a deficient number, since it is larger than the sum of its proper divisors (93925938377).
400030553404303 is an equidigital number, since it uses as much as digits as its factorization.
400030553404303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93925938376.
The product of its (nonzero) digits is 129600, while the sum is 34.
The spelling of 400030553404303 in words is "four hundred trillion, thirty billion, five hundred fifty-three million, four hundred four thousand, three hundred three".
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