Base | Representation |
---|---|
bin | 100101010000011011… |
… | …010001100110110111 |
3 | 10211020221122102200001 |
4 | 211100123101212313 |
5 | 1123412013023301 |
6 | 30213321132131 |
7 | 2614223445451 |
oct | 452033214667 |
9 | 124227572601 |
10 | 40004032951 |
11 | 15a69263063 |
12 | 790532a047 |
13 | 3a06b6511c |
14 | 1d16d3b2d1 |
15 | 1092031c01 |
hex | 9506d19b7 |
40004032951 has 2 divisors, whose sum is σ = 40004032952. Its totient is φ = 40004032950.
The previous prime is 40004032933. The next prime is 40004033023. The reversal of 40004032951 is 15923040004.
40004032951 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40004032951 - 27 = 40004032823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40004032931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20002016475 + 20002016476.
It is an arithmetic number, because the mean of its divisors is an integer number (20002016476).
Almost surely, 240004032951 is an apocalyptic number.
40004032951 is a deficient number, since it is larger than the sum of its proper divisors (1).
40004032951 is an equidigital number, since it uses as much as digits as its factorization.
40004032951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 40004032951 its reverse (15923040004), we get a palindrome (55927072955).
The spelling of 40004032951 in words is "forty billion, four million, thirty-two thousand, nine hundred fifty-one".
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