Base | Representation |
---|---|
bin | 100101010000110101… |
… | …110110101110101111 |
3 | 10211021102202102200201 |
4 | 211100311312232233 |
5 | 1123420304011001 |
6 | 30214130334331 |
7 | 2614336615651 |
oct | 452065665657 |
9 | 124242672621 |
10 | 40011000751 |
11 | 15a72192077 |
12 | 790772a3a7 |
13 | 3a08434797 |
14 | 1d17c326d1 |
15 | 109295b501 |
hex | 950d76baf |
40011000751 has 2 divisors, whose sum is σ = 40011000752. Its totient is φ = 40011000750.
The previous prime is 40011000739. The next prime is 40011000761. The reversal of 40011000751 is 15700011004.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40011000751 - 25 = 40011000719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40011000761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20005500375 + 20005500376.
It is an arithmetic number, because the mean of its divisors is an integer number (20005500376).
Almost surely, 240011000751 is an apocalyptic number.
40011000751 is a deficient number, since it is larger than the sum of its proper divisors (1).
40011000751 is an equidigital number, since it uses as much as digits as its factorization.
40011000751 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 140, while the sum is 19.
Adding to 40011000751 its reverse (15700011004), we get a palindrome (55711011755).
The spelling of 40011000751 in words is "forty billion, eleven million, seven hundred fifty-one", and thus it is an aban number.
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