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40011014121 = 3131025923439
BaseRepresentation
bin100101010000110101…
…111001111111101001
310211021102210010000220
4211100311321333221
51123420304422441
630214130520253
72614340002641
oct452065717751
9124242703026
1040011014121
1115a721a1121
127907736089
133a0843a8b0
141d17c37521
151092960466
hex950d79fe9

40011014121 has 8 divisors (see below), whose sum is σ = 57451712640. Its totient is φ = 24622162512.

The previous prime is 40011014111. The next prime is 40011014129. The reversal of 40011014121 is 12141011004.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 40011014121 - 213 = 40011005929 is a prime.

It is a super-2 number, since 2×400110141212 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 40011014121.

It is not an unprimeable number, because it can be changed into a prime (40011014129) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 512961681 + ... + 512961758.

It is an arithmetic number, because the mean of its divisors is an integer number (7181464080).

Almost surely, 240011014121 is an apocalyptic number.

It is an amenable number.

40011014121 is a deficient number, since it is larger than the sum of its proper divisors (17440698519).

40011014121 is a wasteful number, since it uses less digits than its factorization.

40011014121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1025923455.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 40011014121 its reverse (12141011004), we get a palindrome (52152025125).

The spelling of 40011014121 in words is "forty billion, eleven million, fourteen thousand, one hundred twenty-one".

Divisors: 1 3 13 39 1025923439 3077770317 13337004707 40011014121