Base | Representation |
---|---|
bin | 101101100000000000001001… |
… | …0100001101100011111100111 |
3 | 1221111001220100011210210100111 |
4 | 1123000000102201230133213 |
5 | 404424221232043131401 |
6 | 3535111410450553451 |
7 | 150205060502022304 |
oct | 13300002241543747 |
9 | 1844056304723314 |
10 | 400222543333351 |
11 | 106583477a27902 |
12 | 38a79987b98887 |
13 | 14241a93136b1b |
14 | 70b8c357020ab |
15 | 3140a90758e51 |
hex | 16c001286c7e7 |
400222543333351 has 2 divisors, whose sum is σ = 400222543333352. Its totient is φ = 400222543333350.
The previous prime is 400222543333253. The next prime is 400222543333381. The reversal of 400222543333351 is 153333345222004.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-400222543333351 is a prime.
It is a super-3 number, since 3×4002225433333513 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (400222543333381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200111271666675 + 200111271666676.
It is an arithmetic number, because the mean of its divisors is an integer number (200111271666676).
Almost surely, 2400222543333351 is an apocalyptic number.
400222543333351 is a deficient number, since it is larger than the sum of its proper divisors (1).
400222543333351 is an equidigital number, since it uses as much as digits as its factorization.
400222543333351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 777600, while the sum is 40.
Adding to 400222543333351 its reverse (153333345222004), we get a palindrome (553555888555355).
The spelling of 400222543333351 in words is "four hundred trillion, two hundred twenty-two billion, five hundred forty-three million, three hundred thirty-three thousand, three hundred fifty-one".
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