40023121433 has 2 divisors, whose sum is σ = 40023121434. Its totient is φ = 40023121432.

The previous prime is 40023121427. The next prime is 40023121459. The reversal of 40023121433 is 33412132004.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38756615689 + 1266505744 = 196867^2 + 35588^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40023121433 is a prime.

It is a super-3 number, since 3×40023121433³ (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40023121399 and 40023121408.

It is not a weakly prime, because it can be changed into another prime (40023921433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20011560716 + 20011560717.

It is an arithmetic number, because the mean of its divisors is an integer number (20011560717).

Almost surely, 2^40023121433 is an apocalyptic number.

It is an amenable number.

40023121433 is a deficient number, since it is larger than the sum of its proper divisors (1).

40023121433 is an equidigital number, since it uses as much as digits as its factorization.

40023121433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 40023121433 its reverse (33412132004), we get a palindrome (73435253437).

The spelling of 40023121433 in words is "forty billion, twenty-three million, one hundred twenty-one thousand, four hundred thirty-three".