Base | Representation |
---|---|
bin | 111010010000001101110… |
… | …000010110110110011111 |
3 | 112011200210201201110221122 |
4 | 322100031300112312133 |
5 | 1011041412404101231 |
6 | 12303003421321155 |
7 | 562134356056214 |
oct | 72201560266637 |
9 | 15150721643848 |
10 | 4003140300191 |
11 | 13037a437968a |
12 | 547a037061bb |
13 | 230657593b26 |
14 | dba78427b0b |
15 | 6e1e6a1477b |
hex | 3a40dc16d9f |
4003140300191 has 2 divisors, whose sum is σ = 4003140300192. Its totient is φ = 4003140300190.
The previous prime is 4003140300101. The next prime is 4003140300199. The reversal of 4003140300191 is 1910030413004.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4003140300191 is a prime.
It is a super-3 number, since 3×40031403001913 (a number of 39 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4003140300191.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4003140300199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2001570150095 + 2001570150096.
It is an arithmetic number, because the mean of its divisors is an integer number (2001570150096).
Almost surely, 24003140300191 is an apocalyptic number.
4003140300191 is a deficient number, since it is larger than the sum of its proper divisors (1).
4003140300191 is an equidigital number, since it uses as much as digits as its factorization.
4003140300191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 4003140300191 its reverse (1910030413004), we get a palindrome (5913170713195).
The spelling of 4003140300191 in words is "four trillion, three billion, one hundred forty million, three hundred thousand, one hundred ninety-one".
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