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400400433001141 is a prime number
BaseRepresentation
bin101101100001010010111110…
…1100100111011001010110101
31221111200220111121121020000221
41123002211331210323022311
5404440130041322014031
63535325230343534341
7150223655664163336
oct13302457544731265
91844626447536027
10400400433001141
11106641963014181
1238aa8352a5a3b1
13142557a27b3691
1470c36ad12228d
153145502a58a11
hex16c297d93b2b5

400400433001141 has 2 divisors, whose sum is σ = 400400433001142. Its totient is φ = 400400433001140.

The previous prime is 400400433001133. The next prime is 400400433001183. The reversal of 400400433001141 is 141100334004004.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 361687024561041 + 38713408440100 = 19018071^2 + 6222010^2 .

It is a cyclic number.

It is not a de Polignac number, because 400400433001141 - 23 = 400400433001133 is a prime.

It is a super-3 number, since 3×4004004330011413 (a number of 45 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (400400433001111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200200216500570 + 200200216500571.

It is an arithmetic number, because the mean of its divisors is an integer number (200200216500571).

Almost surely, 2400400433001141 is an apocalyptic number.

It is an amenable number.

400400433001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

400400433001141 is an equidigital number, since it uses as much as digits as its factorization.

400400433001141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 400400433001141 its reverse (141100334004004), we get a palindrome (541500767005145).

The spelling of 400400433001141 in words is "four hundred trillion, four hundred billion, four hundred thirty-three million, one thousand, one hundred forty-one".