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40041013433 is a prime number
BaseRepresentation
bin100101010010101000…
…010110000010111001
310211100112020020100112
4211102220112002321
51124000444412213
630221121514105
72615152666331
oct452250260271
9124315206315
1040041013433
1115a88121043
1279157a2935
133a11712475
141d1bc060c1
1510953d8ea8
hex952a160b9

40041013433 has 2 divisors, whose sum is σ = 40041013434. Its totient is φ = 40041013432.

The previous prime is 40041013379. The next prime is 40041013451. The reversal of 40041013433 is 33431014004.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37254018169 + 2786995264 = 193013^2 + 52792^2 .

It is a cyclic number.

It is not a de Polignac number, because 40041013433 - 234 = 22861144249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40041013399 and 40041013408.

It is not a weakly prime, because it can be changed into another prime (40041013483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20020506716 + 20020506717.

It is an arithmetic number, because the mean of its divisors is an integer number (20020506717).

Almost surely, 240041013433 is an apocalyptic number.

It is an amenable number.

40041013433 is a deficient number, since it is larger than the sum of its proper divisors (1).

40041013433 is an equidigital number, since it uses as much as digits as its factorization.

40041013433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 40041013433 its reverse (33431014004), we get a palindrome (73472027437).

The spelling of 40041013433 in words is "forty billion, forty-one million, thirteen thousand, four hundred thirty-three".