Base | Representation |
---|---|
bin | 100101010010101100… |
… | …100111011000101011 |
3 | 10211100121100010011021 |
4 | 211102230213120223 |
5 | 1124001241224120 |
6 | 30221201513311 |
7 | 2615165341432 |
oct | 452254473053 |
9 | 124317303137 |
10 | 40042133035 |
11 | 15a88816233 |
12 | 7916042837 |
13 | 3a11a14c58 |
14 | 1d1c018119 |
15 | 109555aaaa |
hex | 952b2762b |
40042133035 has 4 divisors (see below), whose sum is σ = 48050559648. Its totient is φ = 32033706424.
The previous prime is 40042133017. The next prime is 40042133057. The reversal of 40042133035 is 53033124004.
40042133035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40042133035 - 211 = 40042130987 is a prime.
It is a super-2 number, since 2×400421330352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4004213299 + ... + 4004213308.
It is an arithmetic number, because the mean of its divisors is an integer number (12012639912).
Almost surely, 240042133035 is an apocalyptic number.
40042133035 is a deficient number, since it is larger than the sum of its proper divisors (8008426613).
40042133035 is an equidigital number, since it uses as much as digits as its factorization.
40042133035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8008426612.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 40042133035 its reverse (53033124004), we get a palindrome (93075257039).
The spelling of 40042133035 in words is "forty billion, forty-two million, one hundred thirty-three thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •