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4004840400013 is a prime number
BaseRepresentation
bin111010010001110011000…
…101101110010010001101
3112011212012012202111110201
4322101303011232102031
51011103403120300023
612303444232333501
7562224451505365
oct72216305562215
915155165674421
104004840400013
111304496aaa862
125481b8b44291
1323086887695b
14dbb9a1379a5
156e295dd7bad
hex3a47316e48d

4004840400013 has 2 divisors, whose sum is σ = 4004840400014. Its totient is φ = 4004840400012.

The previous prime is 4004840399951. The next prime is 4004840400059. The reversal of 4004840400013 is 3100040484004.

4004840400013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2738670841449 + 1266169558564 = 1654893^2 + 1125242^2 .

It is a cyclic number.

It is not a de Polignac number, because 4004840400013 - 213 = 4004840391821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4004843400013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2002420200006 + 2002420200007.

It is an arithmetic number, because the mean of its divisors is an integer number (2002420200007).

Almost surely, 24004840400013 is an apocalyptic number.

It is an amenable number.

4004840400013 is a deficient number, since it is larger than the sum of its proper divisors (1).

4004840400013 is an equidigital number, since it uses as much as digits as its factorization.

4004840400013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 4004840400013 its reverse (3100040484004), we get a palindrome (7104880884017).

The spelling of 4004840400013 in words is "four trillion, four billion, eight hundred forty million, four hundred thousand, thirteen".