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40053433333 is a prime number
BaseRepresentation
bin100101010011010111…
…101110001111110101
310211101101121020020211
4211103113232033311
51124012134331313
630222244025421
72615363365054
oct452327561765
9124341536224
1040053433333
1115a94134321
127919992271
133a14170614
141d1d71a39b
15109653de3d
hex9535ee3f5

40053433333 has 2 divisors, whose sum is σ = 40053433334. Its totient is φ = 40053433332.

The previous prime is 40053433289. The next prime is 40053433349. The reversal of 40053433333 is 33333435004.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39425279364 + 628153969 = 198558^2 + 25063^2 .

It is a cyclic number.

It is not a de Polignac number, because 40053433333 - 29 = 40053432821 is a prime.

It is a super-2 number, since 2×400534333332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40053433295 and 40053433304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40053433373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20026716666 + 20026716667.

It is an arithmetic number, because the mean of its divisors is an integer number (20026716667).

Almost surely, 240053433333 is an apocalyptic number.

It is an amenable number.

40053433333 is a deficient number, since it is larger than the sum of its proper divisors (1).

40053433333 is an equidigital number, since it uses as much as digits as its factorization.

40053433333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58320, while the sum is 31.

Adding to 40053433333 its reverse (33333435004), we get a palindrome (73386868337).

The spelling of 40053433333 in words is "forty billion, fifty-three million, four hundred thirty-three thousand, three hundred thirty-three".