Base | Representation |
---|---|
bin | 111010010110100110110… |
… | …111010101101111101101 |
3 | 112012100112002000011111121 |
4 | 322112212313111233231 |
5 | 1011144442011341023 |
6 | 12310100450420541 |
7 | 562466431464646 |
oct | 72264667255755 |
9 | 15170462004447 |
10 | 4010004012013 |
11 | 13066a67a699a |
12 | 5491ba291751 |
13 | 2311ac58c07c |
14 | dc129c286cd |
15 | 6e4993abd5d |
hex | 3a5a6dd5bed |
4010004012013 has 4 divisors (see below), whose sum is σ = 4016259869148. Its totient is φ = 4003748154880.
The previous prime is 4010004012011. The next prime is 4010004012017. The reversal of 4010004012013 is 3102104000104.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3588436896489 + 421567115524 = 1894317^2 + 649282^2 .
It is a cyclic number.
It is not a de Polignac number, because 4010004012013 - 21 = 4010004012011 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4010004012011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3127927606 + ... + 3127928887.
It is an arithmetic number, because the mean of its divisors is an integer number (1004064967287).
Almost surely, 24010004012013 is an apocalyptic number.
It is an amenable number.
4010004012013 is a deficient number, since it is larger than the sum of its proper divisors (6255857135).
4010004012013 is an equidigital number, since it uses as much as digits as its factorization.
4010004012013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6255857134.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 4010004012013 its reverse (3102104000104), we get a palindrome (7112108012117).
The spelling of 4010004012013 in words is "four trillion, ten billion, four million, twelve thousand, thirteen".
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