Base | Representation |
---|---|
bin | 111010010110100111011… |
… | …101100100010100000001 |
3 | 112012100112202212021220221 |
4 | 322112213131210110001 |
5 | 1011200002043030103 |
6 | 12310101445303041 |
7 | 562466612613052 |
oct | 72264735442401 |
9 | 15170482767827 |
10 | 4010014033153 |
11 | 1306701420a27 |
12 | 549201704a81 |
13 | 2311b168a43b |
14 | dc12b2b6729 |
15 | 6e49a1db1bd |
hex | 3a5a7764501 |
4010014033153 has 2 divisors, whose sum is σ = 4010014033154. Its totient is φ = 4010014033152.
The previous prime is 4010014033133. The next prime is 4010014033177. The reversal of 4010014033153 is 3513304100104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3179260170304 + 830753862849 = 1783048^2 + 911457^2 .
It is a cyclic number.
It is not a de Polignac number, because 4010014033153 - 241 = 1810990777601 is a prime.
It is not a weakly prime, because it can be changed into another prime (4010014033133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005007016576 + 2005007016577.
It is an arithmetic number, because the mean of its divisors is an integer number (2005007016577).
Almost surely, 24010014033153 is an apocalyptic number.
It is an amenable number.
4010014033153 is a deficient number, since it is larger than the sum of its proper divisors (1).
4010014033153 is an equidigital number, since it uses as much as digits as its factorization.
4010014033153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 4010014033153 its reverse (3513304100104), we get a palindrome (7523318133257).
The spelling of 4010014033153 in words is "four trillion, ten billion, fourteen million, thirty-three thousand, one hundred fifty-three".
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