4010132440049 has 2 divisors, whose sum is σ = 4010132440050. Its totient is φ = 4010132440048.

The previous prime is 4010132440003. The next prime is 4010132440051. The reversal of 4010132440049 is 9400442310104.

4010132440049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3920372280049 + 89760160000 = 1979993^2 + 299600^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4010132440049 is a prime.

Together with 4010132440051, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4010132439997 and 4010132440024.

It is not a weakly prime, because it can be changed into another prime (4010132440849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005066220024 + 2005066220025.

It is an arithmetic number, because the mean of its divisors is an integer number (2005066220025).

Almost surely, 2^{4010132440049} is an apocalyptic number.

It is an amenable number.

4010132440049 is a deficient number, since it is larger than the sum of its proper divisors (1).

4010132440049 is an equidigital number, since it uses as much as digits as its factorization.

4010132440049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 32.

The spelling of 4010132440049 in words is "four trillion, ten billion, one hundred thirty-two million, four hundred forty thousand, forty-nine".