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401020283113 = 2631524791951
BaseRepresentation
bin1011101010111101010…
…10111110100011101001
31102100002210102010022021
411311132222332203221
523032242143024423
6504120504224441
740654441110232
oct5653652764351
91370083363267
10401020283113
1114508754a18a
1265878a6b121
132ba7bb2a768
14155a38b0089
15a67128495d
hex5d5eabe8e9

401020283113 has 4 divisors (see below), whose sum is σ = 402545075328. Its totient is φ = 399495490900.

The previous prime is 401020283107. The next prime is 401020283141. The reversal of 401020283113 is 311382020104.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 401020283113 - 217 = 401020152041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (401020283173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 762395713 + ... + 762396238.

It is an arithmetic number, because the mean of its divisors is an integer number (100636268832).

Almost surely, 2401020283113 is an apocalyptic number.

It is an amenable number.

401020283113 is a deficient number, since it is larger than the sum of its proper divisors (1524792215).

401020283113 is a wasteful number, since it uses less digits than its factorization.

401020283113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1524792214.

The product of its (nonzero) digits is 1152, while the sum is 25.

The spelling of 401020283113 in words is "four hundred one billion, twenty million, two hundred eighty-three thousand, one hundred thirteen".

Divisors: 1 263 1524791951 401020283113