Base | Representation |
---|---|
bin | 10010001111001000101111… |
… | …00000101111110100000101 |
3 | 12020222202120110110222100011 |
4 | 21013210113200233310011 |
5 | 20224014412022300143 |
6 | 221142500330550221 |
7 | 11306211302410411 |
oct | 1107442740576405 |
9 | 166882513428304 |
10 | 40102504103173 |
11 | 11861416106a26 |
12 | 45b8173598371 |
13 | 194b85ab12155 |
14 | 9c8d85d37d41 |
15 | 498258be2e9d |
hex | 24791782fd05 |
40102504103173 has 2 divisors, whose sum is σ = 40102504103174. Its totient is φ = 40102504103172.
The previous prime is 40102504103161. The next prime is 40102504103239. The reversal of 40102504103173 is 37130140520104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 36797532813409 + 3304971289764 = 6066097^2 + 1817958^2 .
It is a cyclic number.
It is not a de Polignac number, because 40102504103173 - 213 = 40102504094981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40102504103573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20051252051586 + 20051252051587.
It is an arithmetic number, because the mean of its divisors is an integer number (20051252051587).
Almost surely, 240102504103173 is an apocalyptic number.
It is an amenable number.
40102504103173 is a deficient number, since it is larger than the sum of its proper divisors (1).
40102504103173 is an equidigital number, since it uses as much as digits as its factorization.
40102504103173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
Adding to 40102504103173 its reverse (37130140520104), we get a palindrome (77232644623277).
The spelling of 40102504103173 in words is "forty trillion, one hundred two billion, five hundred four million, one hundred three thousand, one hundred seventy-three".
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