Base | Representation |
---|---|
bin | 100101010110010110… |
… | …000000011100110011 |
3 | 10211111212110111101021 |
4 | 211112112000130303 |
5 | 1124112422042001 |
6 | 30231225120311 |
7 | 2616540361306 |
oct | 452626003463 |
9 | 124455414337 |
10 | 40103315251 |
11 | 1600a30434a |
12 | 7932629097 |
13 | 3a215b704c |
14 | 1d261c2b3d |
15 | 109aae3ba1 |
hex | 956580733 |
40103315251 has 2 divisors, whose sum is σ = 40103315252. Its totient is φ = 40103315250.
The previous prime is 40103315243. The next prime is 40103315303. The reversal of 40103315251 is 15251330104.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40103315251 - 23 = 40103315243 is a prime.
It is not a weakly prime, because it can be changed into another prime (40103315221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20051657625 + 20051657626.
It is an arithmetic number, because the mean of its divisors is an integer number (20051657626).
Almost surely, 240103315251 is an apocalyptic number.
40103315251 is a deficient number, since it is larger than the sum of its proper divisors (1).
40103315251 is an equidigital number, since it uses as much as digits as its factorization.
40103315251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 40103315251 its reverse (15251330104), we get a palindrome (55354645355).
The spelling of 40103315251 in words is "forty billion, one hundred three million, three hundred fifteen thousand, two hundred fifty-one".
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