Base | Representation |
---|---|
bin | 10010001111001011101011… |
… | …00001000101011111111101 |
3 | 12020222220122101011100110202 |
4 | 21013211311201011133331 |
5 | 20224031124300002201 |
6 | 221143321030413245 |
7 | 11306265343060115 |
oct | 1107456541053775 |
9 | 166886571140422 |
10 | 40104081250301 |
11 | 11862055399a02 |
12 | 45b8533801225 |
13 | 194ba4c7a60c3 |
14 | 9c90955a0045 |
15 | 4982ec3cac6b |
hex | 2479758457fd |
40104081250301 has 2 divisors, whose sum is σ = 40104081250302. Its totient is φ = 40104081250300.
The previous prime is 40104081250267. The next prime is 40104081250327. The reversal of 40104081250301 is 10305218040104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34784646418201 + 5319434832100 = 5897851^2 + 2306390^2 .
It is a cyclic number.
It is not a de Polignac number, because 40104081250301 - 222 = 40104077055997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40104081258301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20052040625150 + 20052040625151.
It is an arithmetic number, because the mean of its divisors is an integer number (20052040625151).
Almost surely, 240104081250301 is an apocalyptic number.
It is an amenable number.
40104081250301 is a deficient number, since it is larger than the sum of its proper divisors (1).
40104081250301 is an equidigital number, since it uses as much as digits as its factorization.
40104081250301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 29.
Adding to 40104081250301 its reverse (10305218040104), we get a palindrome (50409299290405).
The spelling of 40104081250301 in words is "forty trillion, one hundred four billion, eighty-one million, two hundred fifty thousand, three hundred one".
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