401099353153 has 4 divisors (see below), whose sum is σ = 418538455488. Its totient is φ = 383660250820.

The previous prime is 401099353147. The next prime is 401099353159. The reversal of 401099353153 is 351353990104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (401099353147) and next prime (401099353159).

It is a cyclic number.

It is not a de Polignac number, because 401099353153 - 2²⁹ = 400562482241 is a prime.

It is a super-2 number, since 2×401099353153² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (401099353159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8719551133 + ... + 8719551178.

It is an arithmetic number, because the mean of its divisors is an integer number (104634613872).

Almost surely, 2^401099353153 is an apocalyptic number.

It is an amenable number.

401099353153 is a deficient number, since it is larger than the sum of its proper divisors (17439102335).

401099353153 is a wasteful number, since it uses less digits than its factorization.

401099353153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17439102334.

The product of its (nonzero) digits is 218700, while the sum is 43.

The spelling of 401099353153 in words is "four hundred one billion, ninety-nine million, three hundred fifty-three thousand, one hundred fifty-three".