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401113443347 is a prime number
BaseRepresentation
bin1011101011001000011…
…10010110110000010011
31102100100021201011010022
411311210032112300103
523032440020141342
6504134033054055
740656652004351
oct5654416266023
91370307634108
10401113443347
11145125099911
12658a40b732b
132ba95217c66
14155b20007d1
15a6795379d2
hex5d64396c13

401113443347 has 2 divisors, whose sum is σ = 401113443348. Its totient is φ = 401113443346.

The previous prime is 401113443329. The next prime is 401113443349. The reversal of 401113443347 is 743344311104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 401113443347 - 214 = 401113426963 is a prime.

It is a super-3 number, since 3×4011134433473 (a number of 36 digits) contains 333 as substring.

Together with 401113443349, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (401113443349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200556721673 + 200556721674.

It is an arithmetic number, because the mean of its divisors is an integer number (200556721674).

Almost surely, 2401113443347 is an apocalyptic number.

401113443347 is a deficient number, since it is larger than the sum of its proper divisors (1).

401113443347 is an equidigital number, since it uses as much as digits as its factorization.

401113443347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 35.

The spelling of 401113443347 in words is "four hundred one billion, one hundred thirteen million, four hundred forty-three thousand, three hundred forty-seven".