401132021 has 2 divisors, whose sum is σ = 401132022. Its totient is φ = 401132020.

The previous prime is 401131999. The next prime is 401132077. The reversal of 401132021 is 120231104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 315772900 + 85359121 = 17770^2 + 9239^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-401132021 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 401131987 and 401132005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401132821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200566010 + 200566011.

It is an arithmetic number, because the mean of its divisors is an integer number (200566011).

Almost surely, 2^401132021 is an apocalyptic number.

It is an amenable number.

401132021 is a deficient number, since it is larger than the sum of its proper divisors (1).

401132021 is an equidigital number, since it uses as much as digits as its factorization.

401132021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 401132021 is about 20028.2805302902. The cubic root of 401132021 is about 737.5007119020.

Adding to 401132021 its reverse (120231104), we get a palindrome (521363125).

The spelling of 401132021 in words is "four hundred one million, one hundred thirty-two thousand, twenty-one".