Base | Representation |
---|---|
bin | 111010010111110110110… |
… | …010110011011110001111 |
3 | 112012110222112022102122202 |
4 | 322113312302303132033 |
5 | 1011210213310002320 |
6 | 12310441512432115 |
7 | 562544603630621 |
oct | 72276662633617 |
9 | 15173875272582 |
10 | 4011345000335 |
11 | 130722474a302 |
12 | 5495133a863b |
13 | 23136434869a |
14 | dc215d78c11 |
15 | 6e526e96b75 |
hex | 3a5f6cb378f |
4011345000335 has 16 divisors (see below), whose sum is σ = 4962427025472. Its totient is φ = 3110864390400.
The previous prime is 4011345000329. The next prime is 4011345000359. The reversal of 4011345000335 is 5330005431104.
It is a de Polignac number, because none of the positive numbers 2k-4011345000335 is a prime.
It is a super-2 number, since 2×40113450003352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4011345000298 and 4011345000307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62284811 + ... + 62349180.
It is an arithmetic number, because the mean of its divisors is an integer number (310151689092).
Almost surely, 24011345000335 is an apocalyptic number.
4011345000335 is a deficient number, since it is larger than the sum of its proper divisors (951082025137).
4011345000335 is a wasteful number, since it uses less digits than its factorization.
4011345000335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 124634194.
The product of its (nonzero) digits is 10800, while the sum is 29.
The spelling of 4011345000335 in words is "four trillion, eleven billion, three hundred forty-five million, three hundred thirty-five", and thus it is an aban number.
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